Question

The solution of the pair of linear equations 3 x + 2 y = 4 and 8 x + 5 y = 0 is *
x = 2, y = -5
x = -2, y = 5
x = -2, y = -5
None​

Answer 1

Answer:

(d) None of the above       The actual answer is x = -20 and y = 32

Step-by-step explanation:

3x+2y = 4

8x+5y = 0

By elimination method, multiply first equation by 5 and second equation by 2 to make coefficient of y same.

15x+10y =  20

16x+10y =  0

As signs of y are same , subtract

15x - 16 x = 20

x =  -20

Now , 3x+2y = 4

          3(-20) +2y = 4

           2y = 4+60

           2y = 64

             y = 32

Answer 2

Answer:

3x+2y=4-----(1)

8x+5y=0-----(2)

multiply equation (1)by 5 and equation (2) by 2

after multiplication we get :

15x+10y=20----(3)

16x+10y=0-----(4)

now, subtract (3) and (4)

result:

X=-20

there fore the answer is none