The solution of the quadratic equation 6x^2-5x-21=0 are
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=>6x²-5x-21=0
It is in the form of a quadratic equation so we use quadratic formula for finding the roots
quadratic formula to find roots :
x= -b±√b²-4ac / 2a
From above Equation
using the quadratic formula where ,
a= 6 ,b = -8 and c= -21
=>x= -(-5) ± √(-5)²-4(6)(-21) / 2(6)
=>x= 5±√25-(-504) / 12
=>x= 5±√25+504 / 12
=>x=5±√529 / 12
The discriminant b²-4ac is >0
So,there are two real roots of this Equation.
=>x= 5± 23/12
=>x=28/12 ; x= -18/12
x= 2.33333
x= -1.5
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