Question

The solution of the quadratic equation x² - 20x - 44 = 0 is __________.​

Answer 1

GIVEN :-

• A quadratic equation x² - 20x - 44 = 0.

TO FIND :-

• The zeroes of the given quadratic equation.

SOLUTION :-

$\\ : \implies \displaystyle \sf x ^{2} - 20x - 44 = 0$

$: \implies \displaystyle \sf \:x ^{2} - 22x + 2x - 44 = 0$

$: \implies \displaystyle \sf x(x - 22) + 2(x - 22) = 0$

$: \implies \displaystyle \sf \: (x + 2)(x - 22) = 0$

$: \implies \displaystyle \sf \: x + 2 = 0 \: , \: x - 22 = 0$

$: \implies \underline{ \boxed{ \displaystyle \sf \bold{\:x = - 2 \: , \: x = 22}}}$

$\boxed{\begin{minipage}{5.5 cm} { \bigstar\: \textsf{For a Quadratic Polynomial :}}\\\\ {\qquad\sf p(x) = ax ^\sf2 \sf + bx + c}\\\sf with zeroes \alpha\:\sf and\:\beta \\\\\\ {\textcircled{\footnotesize1}} \:\:\alpha +\beta= \dfrac{ - \:b}{a}\:\:\bigg\lgroup\bf Sum\:of\:Zeroes\bigg\rgroup \\\\\\{\textcircled{\footnotesize2}} \: \:\alpha \beta= \sf\dfrac{c}{a}\:\:\bigg\lgroup\bf Product\:of\:Zeroes\bigg\rgroup\end{minipage}}$

Answer 2

Answer:

Question

the solution of the quadratic equation x² - 20x - 44 = 0 is __________.

To find

solution of the quadratic equation

Solution

➡️ x² - 20x -44=0

➡️ x² −22x+2x−44=0

➡️ x (x-22) +2 (x - 22) = 0

➡️ (x+2)(x−22)=0

➡️ Break the bracket

➡️ x+2 x-22 = 0

➡️ So the solution of the quadratic equation x² - 20x - 44 = 0 is

x = -2 , x = 22

$\sf Hope it helps$