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rakeshsarkar1:
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let no. of black balls be X
so total no. of balls = 30+X
probability to get a black ball = X/30+X
and probability to get a white ball = 30/30+X
ACC. to qué
X/(30+X)=2*30/5*(30+X)
so X=12
is Ur required result in attachment
so total no. of balls = 30+X
probability to get a black ball = X/30+X
and probability to get a white ball = 30/30+X
ACC. to qué
X/(30+X)=2*30/5*(30+X)
so X=12
is Ur required result in attachment
Attachments:
Answered by
1
No. Of black balls=x Tot no of balls = 30+x. Probability of getting a white ball =30/x+30. Probability of getting a black ball=2/5into30/x+30. Sum of both probability =1. Equate them you'll get it DSTG
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