THE SOLUTION OF THIS QUESTION
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Consider 4a2 - 9b2 - 2a - 3b = (2a)2 – (3b)2 – 2a – 3b = (2a – 3b)(2a + 3b) – 1(2a + 3b) = (2a + 3b)[(2a – 3b) – 1] = (2a + 3b)[2a – 3b – 1]
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