Question

the solution of x/2-1/2=3 is?​

Answer 1

Answer:

Multiply the numbers

2−1⋅12=3

\frac{x}{2}{\color{#c92786}{-1}} \cdot {\color{#c92786}{\frac{1}{2}}}=32x−1⋅21=3

2−12=3

\frac{x}{2}{\color{#c92786}{-\frac{1}{2}}}=32x−21=3

2

Find common denominator

2−12=3

\frac{x}{2}-\frac{1}{2}=32x−21=3

2+2(−12)2=3

\frac{x}{2}+\frac{2\left(-\frac{1}{2}\right)}{2}=32x+22(−21)=3

3

Combine fractions with common denominator

2+2(−12)2=3

\frac{x}{2}+\frac{2\left(-\frac{1}{2}\right)}{2}=32x+22(−21)=3

+2(−12)2=3

\frac{x+2\left(-\frac{1}{2}\right)}{2}=32x+2(−21)=3

4

Multiply the numbers

+2(−12)2=3

\frac{x+{\color{#c92786}{2}}\left({\color{#c92786}{-\frac{1}{2}}}\right)}{2}=32x+2(−21)=3

−12=3

\frac{x{\color{#c92786}{-1}}}{2}=32x−1=3

5

Multiply all terms by the same value to eliminate fraction denominators

−12=3

\frac{x-1}{2}=32x−1=3

2⋅−12=2⋅3

2 \cdot \frac{x-1}{2}=2 \cdot 32⋅2x−1=2⋅3

6

Cancel multiplied terms that are in the denominator

2⋅−12=2⋅3

2 \cdot \frac{x-1}{2}=2 \cdot 32⋅2x−1=2⋅3

−1=2⋅3

x-1=2 \cdot 3x−1=2⋅3

7

Multiply the numbers

−1=2⋅3

x-1={\color{#c92786}{2}} \cdot {\color{#c92786}{3}}x−1=2⋅3

−1=6

x-1={\color{#c92786}{6}}x−1=6

8

Add 

1

11

 to both sides of the equation

−1=6

x-1=6x−1=6

−1+1=6+1

x-1+{\color{#c92786}{1}}=6+{\color{#c92786}{1}}x−1+1=6+1

9

Simplify

Add the numbers