Question

the solution of (x+2)²-(x-3)²=5 is​

Answer 1

Answer:

(x+2)^2-(x-3)^2=5

x^2+4+4x-(x^2+9-6x)=5

x^2+4+4x-x^2-9+6x=5

4+4x-9+6x=5

10x-5=5

10x=10

x=10

Answer 2

X will be equivalent to 1 in value.

Given:

The solution is $(x+2)^{2} - (x - 3)^{2} = 5$

To Find:

The value of x

Solution:

It's fairly simple to find the answer to this question, as seen below.

We have the equation,

$(x+2)^{2} - (x - 3)^{2} = 5$

We know that,

$(a+b)^{2} = a^{2} + b^{2} + 2ab\\(a-b)^{2} = a^{2} + b^{2} - 2ab$

By simplifying the given equation like this,

$x^{2} + 2^{2} + 2$ × $x$ × $2$ $-$ $x^{2} + 3^{2} - 2$ × $x$ × $3$ $= 5$

$(x^{2}+4+4x) - (x^{2}+9-6x) = 5$

On opening brackets,

$x^{2} + 4 + 4x - x^{2} - 9 + 6x = 5$

$4 + 4x - 9 + 6x = 5$

$10x - 5 = 5$

$10x = 10$

$x = \frac{10}{10}$

$x = 1$

Hence, the value of x will be equal to 1.

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