Question

The solution of x^2+2x-4=0 are

Answer 1

$x = 1 + \sqrt{5} \: , \: 1 - \sqrt{5}$

Step-by-step explanation:

${x}^{2} + 2x - 4 = 0$

${x}^{2} + 2x = 4$

${x}^{2} + 2x + 1 = 5$

${(x + 1)}^{2} = 5$

$x + 1 = | \sqrt{5} |$

$x = 1 + \sqrt{5}$

$x = 1 - \sqrt{5}$

Hope it helps

Answer 2

Answer:

HEY FRIEND,I THINK I CAN HELP YOU.

Step-by-step explanation:

we can use middle term factorisation method

for finding value of x.

Given,

x^2+2x-4=0

now, we have to consider two number whose sum will be 2x and product will be 4x^2.

x^2+4x-2x-4=0

Here ,roots are not possible . Please note it.

because if D=b^2-4ac

Then,it's value will be in negative (-12)