Math, asked by wazeermd7512, 11 months ago

The solution of x for the equation x2-(√3+1)x+√3=0 is

Answers

Answered by Anonymous
0

Here,

x²-(√3+1)x+√3=0

To find the roots of the equation,i.e.,the solutions of x

Now,

x²-(√3+1)x+√3=0

→x²-√3x-x+√3=0

→x(x-√3)-1(x-√3)=0

→(x-1)(x-√3)=0

→x-1=0 or x-√3=0

→x=1 or x=√3

The roots of the equation are 1 and √3.

Answered by Panzer786
0

Step-by-step explanation:

Hi,

X² - ( √3 + 1 )x + √3 = 0

X² - √3X - x + √3 = 0

x ( x - √3 ) -1 ( x - √3 ) = 0

( x - √3 ) ( x - 1 ) = 0

( x - √3 ) = 0 or ( x - 1 ) = 0

x = √3 or x = 1.

Hope it will help you:)

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