Question

The solution of (y+z)dx + dy+dz=0 is​

Answer 1

Answer:

y + z = $ce^{-x}$

Step-by-step explanation:

(y+z)dx+dy+dz=0

⇒ dx+dy+dz / y+z=0

⇒ dx+d(y+z) / y+z=0

Integrating,

x+log(y+z)=logc

x=logc / y+z

e^x=c / y+z

y+z=ce^−x

Hope helps!