the solution set of (ax+b) (cx-d)=0 is
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Given that :-
(ax+b)(cx−d)=0
by Equating the factors individually to zero we will get:
(ax+b)=0 ax=−bx=−ba
(cx−d)=0cx=dx=dc
So from above solution we can say that the solution set is: {−ba,dc}
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The solution set of the equation is {−b/a, d/c}.
Definition of solution set
- The set of values that satisfy a given set of equations or inequalities is referred to as a solution set.
- For example, the solution set for a collection of polynomials over a ring is the subset of on which all of the polynomials vanish (evaluate to 0).
Given:
(ax + b)(cx − d)=0
Explanation:
Equating the factors individually to zero, the result comes
(ax + b)=0
ax = −b
x = −b/a
Similarly, solve for other factor.
(cx − d) = 0
cx = d
x = d/c
Thus from the above simplification the solution set found as {−b/a,d/c}.
To know about zeros of polynomial, here
https://brainly.in/question/1374519?msp_poc_exp=2
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