Math, asked by gmanjularao3, 2 months ago

The solution set of
log_1/2 (x^2-1)>0 is​

Answers

Answered by senboni123456
0

Step-by-step explanation:

We have,

 log_{ \frac{1}{2} }( {x}^{2} - 1 ) > 0 \\

 \implies ( {x}^{2} - 1 ) < 1\\

 \implies ( {x}^{2} - 2 ) < 0\\

 \implies ( x -  \sqrt{2} )(x +  \sqrt{2})  < 0\\

 \implies x \in( -  \sqrt{2}  ,\sqrt{2} )

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