the solution set of the equation 2x + 3 Mod minus Mod x minus 1 equal to 6
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we have to find the value of |2x + 3| - |x - 1| = 6
first break the modulus function,
2x + 3 = 0 ⇒x = -3/2
x - 1 = 0 ⇒ x = 1
case 1 : when x > 1
2x + 3 - (x - 1) = 6
⇒2x + 3 - x + 1 = 6
⇒x = 2
case 2 : when -3/2 ≤ x ≤ 1
2x + 3 + (x - 1) = 6
⇒3x + 2 = 6
⇒x = 4/3 but -3/2 ≤ x ≤ 1
so, x ≠ 4/3 hence in this case there is no solution.
case 3 : when x < -3/2
-(2x + 3) + (x - 1) = 6
⇒-2x - 3 + x - 1 = 6
⇒- x - 4 = 6
⇒x = -10
therefore, solution of given equation is x = 2 , -10
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1
Step-by-step explanation:
answer of this questions is 2,-10
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