Question

The solution set of x/2 – 5 ≤ x/3 – 4, where x is a positive odd integer is​

Answer 1

$\frac{x}{2} + 5 \leqslant \frac{x}{3} + 6$

$\frac{x}{2} - \frac{x}{3} \leqslant 6 - 5$

$\frac{x}{6} \leqslant 1$

$x \leqslant 6$

$since \: x \: is \: a \: positive \: odd \: integer$

therefore solution set ={1,3,5}