Question

: The solution set of (x-2)(x+1) = 0 is​

Answer 1

Answer:

x^2 + x -2x-2 = 0

x^2 -x -2 = 0

x^2 -2x+x -2 = 0

x ( x -2 ) +1 ( x-2) = 0

(x+1)(x-2) = 0

x+1 = 0

x= -1

or

x-2 = 0

x = 2