The solution set of x–3y=1 and 3x+y=3 is ......,select a proper option (a), (b), (c) or (d) from given options so that the statement becomes correct.
(a) {(0, 1)}
(b) {(1, 1)}
(c) {(1, 0)}
(d) {(1/3,0)}
Answers
Answered by
4
hy mate (c) is the YOUR ANSHWER
Answered by
9
Option ( c ) is correct.
Explanation :
Given pair of linear equations,
x - 3y = 1
=> x = 1 + 3y ---( 1 )
3x + y = 3 -----( 2 )
Substitute x = 1 + 3y in equation ( 2 ),
We get,
3( 1 + 3y ) + y = 3
=> 3 + 9y + y = 3
=> 10y = 3 - 3
=> y = 0/10
=> y = 0
Put y = 0 in equation ( 1 ) , we get
x = 1 + 3 × 0
=> x = 1
Therefore ,
( x , y ) = ( 1 , 0 )
••••••
Explanation :
Given pair of linear equations,
x - 3y = 1
=> x = 1 + 3y ---( 1 )
3x + y = 3 -----( 2 )
Substitute x = 1 + 3y in equation ( 2 ),
We get,
3( 1 + 3y ) + y = 3
=> 3 + 9y + y = 3
=> 10y = 3 - 3
=> y = 0/10
=> y = 0
Put y = 0 in equation ( 1 ) , we get
x = 1 + 3 × 0
=> x = 1
Therefore ,
( x , y ) = ( 1 , 0 )
••••••
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