Question

the solution set of x>0 and y<1 is​

Answer 1

Answer:

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Answer 2

(1+y2)dx+(1+x2)dy=0

⇒1+x2−dx=1+y2dy

⇒−tan−1x=tan−1y−c

c=tan−1x+tan−1y

⇒c=tan−1(1−xyx+y)

⇒tan c=(1−xyx+y)

But given particular solution (x,y)=(0,1)

⇒tan c=−1

⇒−1=1−xyx+y

xy−1=x+y

⇒x+y+1=xy