Math, asked by dipakgupta7694, 7 months ago

The solution setfor the equation modulus X + 2 is less than or equal to 5 ?

Answers

Answered by varadad25
1

Answer:

The solution set for the given equation is

\displaystyle{\boxed{\pink{\sf\:x\:\in\:\{\:-\:7,\:-\:6,\:-\:5,\:-\:4,\:-\:3,\:-\:2,\:-\:1,\:0,\:1,\:2,\:3\:\}\:}}}

Step-by-step-explanation:

The given inequality is

\displaystyle{\sf\:|\:x\:+\:2\:|\:\leq\:5}

We have to find the value of x.

Now, we know that,

If \displaystyle{\sf\:|\:x\:|\:\leq\:a}, then

\displaystyle{\boxed{\green{\sf\:x\:\leq\:a}}\sf\:\quad\:OR\:\quad\:\boxed{\green{\sf\:x\:\geq\:-\:a}}}

Now,

\displaystyle{\sf\:|\:x\:+\:2\:|\:\leq\:5}

\displaystyle{\implies\sf\:x\:+\:2\:\leq\:5\:\quad\:OR\:\quad\:x\:+\:2\:\geq\:-\:5}

\displaystyle{\implies\sf\:x\:\leq\:5\:-\:2\:\quad\:OR\:\quad\:x\:\geq\:-\:5\:-\:2}

\displaystyle{\implies\sf\:x\:\leq\:3\:\quad\:OR\:\quad\:x\:\geq\:-\:7}

\displaystyle{\therefore\:\boxed{\blue{\sf\:-\:7\:\leq\:x\:\leq\:3\:}}}

\displaystyle{\implies\:\underline{\boxed{\red{\sf\:x\:\leq\:3}}}\sf\:\quad\:OR\:\quad\:\underline{\boxed{\red{\sf\:x\:\geq\:-\:7\:}}}}

The solution set for the given equation

\displaystyle{\boxed{\pink{\sf\:x\:\in\:\{\:-\:7,\:-\:6,\:-\:5,\:-\:4,\:-\:3,\:-\:2,\:-\:1,\:0,\:1,\:2,\:3\:\}\:}}}

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