the solution system of equations x+y=8 and 2x-3y= 1 is
Answers
Answered by
0
Answer:
The equations are x+y = 8 and 2x-3y = 1
Multiplying x+y = 8 by 2
2x+2y = 16
Subtracting 2x + 2y = 16 from 2x-3y = 1
-5y = -15
y = 3
Putting y = 3 in x+y = 8
x = 5
Step-by-step explanation:
Answered by
8
Answer:
Step 1) Solve the first equation for
x
:
x
+
y
=
8
x
+
y
−
y
=
8
−
y
x
+
0
=
8
−
y
x
=
8
−
y
Step 2) Substitute
(
8
−
y
)
for
x
in the second equation and solve for
y
:
2
x
−
3
y
=
1
becomes:
2
(
8
−
y
)
−
3
y
=
1
(
2
⋅
8
)
−
(
2
⋅
y
)
−
3
y
=
1
16
−
2
y
−
3
y
=
1
16
−
5
y
=
1
−
16
+
16
−
5
y
=
−
16
+
1
0
−
5
y
=
−
15
−
5
y
=
−
15
−
5
y
−
5
=
−
15
−
5
−
5
y
−
5
=
3
y
=
3
Step 3) Substitute
3
for
y
in the solution to the first equation at the end of Step 1 and calculate
x
:
x
=
8
−
y
becomes:
x
=
8
−
3
x
=
5
The Solution Is:
x
=
5
and
y
=
3
or
(
5
,
3
)
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