Question

the solution system of equations x+y=8 and 2x-3y= 1 is​

Answer 1

Answer:

The equations are  x+y = 8  and 2x-3y = 1

Multiplying x+y = 8 by 2

2x+2y = 16

Subtracting 2x + 2y = 16 from 2x-3y = 1

-5y = -15

y = 3

Putting y = 3 in x+y = 8

x = 5

Step-by-step explanation:

Answer 2

Answer:

Step 1) Solve the first equation for

x

:

x

+

y

=

8

x

+

y

−

y

=

8

−

y

x

+

0

=

8

−

y

x

=

8

−

y

Step 2) Substitute

(

8

−

y

)

for

x

in the second equation and solve for

y

:

2

x

−

3

y

=

1

becomes:

2

(

8

−

y

)

−

3

y

=

1

(

2

⋅

8

)

−

(

2

⋅

y

)

−

3

y

=

1

16

−

2

y

−

3

y

=

1

16

−

5

y

=

1

−

16

+

16

−

5

y

=

−

16

+

1

0

−

5

y

=

−

15

−

5

y

=

−

15

−

5

y

−

5

=

−

15

−

5

−

5

y

−

5

=

3

y

=

3

Step 3) Substitute

3

for

y

in the solution to the first equation at the end of Step 1 and calculate

x

:

x

=

8

−

y

becomes:

x

=

8

−

3

x

=

5

The Solution Is:

x

=

5

and

y

=

3

or

(

5

,

3

)