The solution to the following differential equation y′′+9y=0, y(0)=1,y′(0)=3 is
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Given y'' + 9y = 0
y'' = - 9y
On integrating on the both sides,
y' = - 9y²/2 + c
On substituting the given values and further solving we can get the values of c.
Put the value of c in the above bolded eqn. to get the GENERAL SOLUTION.
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