the solutions of the eqution x2+bx+c are 3 and 5 then find b&c
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• If 3 &5 are solution of equation x^2+bx+c, then;
3^2 + 3b + c = 0
5^2 + 5b + c = 0
• c= -9-3b
c = -25-5b
• 9+3b = 25+5b
-2b = 16
b = -8
• c = -9-3b
= 24-9
= 15
hence b= -8 & c=15.
hope this helped you ........!
3^2 + 3b + c = 0
5^2 + 5b + c = 0
• c= -9-3b
c = -25-5b
• 9+3b = 25+5b
-2b = 16
b = -8
• c = -9-3b
= 24-9
= 15
hence b= -8 & c=15.
hope this helped you ........!
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