Question

the solutions of (x²+1/x²)-5(x+1/x)+6=0 when x≠0​

Answer 1

Answer:

x^2+1/x^2 -5(x+1/x) +6=0

x^4+1/x^2 -- 5x^2-5/x+6=0

x^4+1-5x^2-5x+6/x^2=0

x^4-5x^3-5x+5=0

x=-3/2