The some of three consecutive multiple of 11 is 363 find these multiple
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363× 11 is the solution for the given question
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so let. x,x+11,x+22be the three consecutive multiples of eleven
x+x+11+x+22=363
3x+33=363
3x=363-33
3x=330
x=330/3
x=110
therefore the three multiples are x=110
x+11=121
x+22=132.
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