the some of three consecutive natural number is 99.find the number.
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x+x+1+x+2=99
3x+3=99
3x=96
x=96/3
x=32
x+1 = 32+1
=33
x+2 = 32+2
=34
3x+3=99
3x=96
x=96/3
x=32
x+1 = 32+1
=33
x+2 = 32+2
=34
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