Question

The some of two numbers is 520. if the bigger no. is decreased by 4% and the smaller no. is increased by 12%, then the numbers obtained are equal. the smaller no. is?

Answer 1

Answer:

• Bigger number = 280
• Smaller number = 240

Step-by-step explanation:

Given:

• Sum of two numbers = 520
• If bigger number is decreased by 4% and smaller number increased by 12%, then numbers obtained are equal.

To Find:

• The numbers.

Let bigger number be 'x'.

And Smaller number be '520 - x'.

Now according to question,

=> x × (100 - 4)/100 = (520 - x) × (100 + 12)/100

=> x × 96/100 = (520 - x) × 112/100

=> 96x/100 = (58240 - 112x)/100

=> 96x = 58240 - 112x

=> 96x + 112x = 58240

=> 208x = 58240

=> x = 58240/208

=> x = 280

Hence,

• Bigger number = 280
• Smaller number = 520 - 280 = 240.

Answer 2

AnswEr :

Smaller no.240

$\bf{\pink{\underline{\underline{\bf{Given\::}}}}}$

The some of two numbers is 520. If the bigger number is decreased by 4% and the smaller number is increased by 12%,the number obtained are equal.

$\bf{\pink{\underline{\underline{\bf{To\:find\::}}}}}$

The number number.

$\bf{\pink{\underline{\underline{\bf{Explanation\::}}}}}$

Let the bigger number be r

Let the smaller number be (520 - r)

A/q

$\mapsto\sf{r\times \dfrac{(100-4)}{100} =520-r\times \dfrac{(100+12)}{100} }\\\\\\\mapsto\sf{r\times \dfrac{96}{100} =520-r\times \dfrac{112}{100} }\\\\\\\mapsto\sf{\dfrac{96r}{\cancel{100}} =(520-r)\times \dfrac{112}{\cancel{100}} }\\\\\\\mapsto\sf{96r=(520-r)\times 112}\\\\\\\mapsto\sf{96r=520\times 112-112r}\\\\\\\mapsto\sf{96r+112r=520\times 112}\\\\\\\mapsto\sf{208r=58240}\\\\\\\mapsto\sf{r=\cancel{\dfrac{58240}{208} }}\\\\\\\mapsto\sf{\red{r=280}}$

Thus;

$\underbrace{\sf{The\:smaller\:number\:=(520-r)=520-280=240}}}}}$