Math, asked by omkaritanale, 2 months ago

the son's age is one-third that of his father .five years ago father's age was 4 times as old as his soon . Find their percentage​

Answers

Answered by Amrit111Raj82
2
  • To find their present ages we will first let the father's age be x.

  • Then, son's age will be x/3. Five years ago son's age will be (x/3 - 5) and father's age will be (x - 5).

  • It is given father's age was 4 times son's age.

Answered by SriThanvi
1

let the fathers age be x

then the son age will be x/3

five years ago

son age = ( x/3 - 5 )

fathers age = ( x- 5 )

five years ago father age was 4 times his son age

x - 5 = 4( x/3 - 5 )

x - 5 = 4x/3 - 20

x - 4x/3 = 5 - 20

(3x - 4x) /3 = -15

-x = -15 × 3

-x = -45

x = 45

hence the value of x is 45

father age is 45 yrs

son age is 45/3 = yrs

and I think in the question you must type present age rather than percentage

Similar questions