The son's present age is half the present age of his mother. Ten years ago, the mother was thrice as old as her son. What are their present ages?
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Given:-
- Perimeter age of the son is half the perimeter age of his mother.
- The year age, the mother was thrice as old her son.
To find:-
- Find the present age of son and mother..?
Solutions:-
- Let the present age of son be x years.
- Let the present age of mother be y years.
Present age of the son is half the present age of his mother.
=> y = 2x ..........(i).
Ten years age, the mother was thrice as old as her son.
- Mother's age = (y - 10) years
- Son's age = (x - 10) years
=> y - 10 = 3(x - 10)
=> y - 10 = 3x - 30
=> y - 3x = -30 + 10
=> y - 3x = -20
Putting the value of y from Eq (i).
=> 2x - 3x = -20
=> -x = -20
=> x = 20
Putting the value of x in Eq (i).
=> y = 2x
=> y = 2 × 20
=> y = 40
Hence, the present age of mother and son are 40 years and 20 years.
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