Question

The son's present age is one third of his father. After 10 year the age of father is twice the age of his son. Find their present age.

Answer 1

Answer:

son's age= 10 years

father's age= 30 years

Step-by-step explanation:

let father's age be x

so, son's age is 1/3x

after 10 years:

son's age= 1/3x+10

father's age= x+10

according to the question:

x+10= 2(1/3x+10)

x+10= 2/3x+20

x-2/3x=10

1/3x=10 years

x=30 years

Done...

hope this helps!

Answer 2

Answer:

7:3

Let the ages of father and son 10 years ago be 3x and x years respectively.

Then, (3x+10)+10=2[(x+10)+10]

⇒3x+20=2x+40

⇒x=20

∴ Required ratio =(3x+10):(x+10)=70:30=7:3

Step-by-step explanation:

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