Question

The sonic boom of an aircraft was attempted of 0.00002 second calculate the frequency of the sound produced

Answer 1

Answer:

The answer is 50000Hz

Explanation:

as we know that:-

Time period= 1 / frequency

Then, 0.00002 sec = 1 / frequency

2 / 100000 = 1/ frequency

Frequency = 100000 / 2

Frequency = 50000Hz

Hope it is helpful

Answer 2

The frequency of the sound produced is 50 kHz.

Explanation:

It is given that,

Time taken by sonic boom, T = 0.00002 s

We need to find the frequency of the sound produced. We know that the frequency of any sound is reciprocal of its time period. It is given by :

$T=\dfrac{1}{f}$

$f=\dfrac{1}{T}$

$f=\dfrac{1}{0.00002\ s}$

f = 50000 Hz

or

f = 50 kHz

So, the frequency of the sound produced is 50 kHz. Hence, this is the required solution.

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