Question

The sound of a mosquito is produced when it vibrates it's wings at an average rate of 500 vibrations per second, what is the time period of the vibration? ​

Answer 1

Answer:

Frequency = 500 vibrations/second. = (1/500) = 0.002 sec.

Explanation:

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Answer 2

Given:

• Frequency of vibrations = 500 Hz

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To find:

• Time period of vibration

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Solution:

Firstly let's understand what's the difference between time period and frequency of vibrations.

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☆ Number of vibrations made per second by a vibrating body is called frequency. SI unit is Hertz (Hz).

Represented by greek letter nu (v).

☆ Time taken to complete one oscillation or vibration is known as time period. SI unit is seconds (s).

Represented by capital t (T).

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Moving on to the question now.

We are given that frequency of vibrations is 500Hz. We have to find the time period of vibrations.

We know that,

$\boxed {\bf {\red {Time\ period = \dfrac {1}{Frequency}}}}$

So,

$\implies \sf T = \dfrac {1}{500}$

$\implies \sf T = \dfrac {2}{1000}$

$\boxed {\bf {\orange {Time\ period = 0.002\ s}}}$

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Final answer:

Time period of the vibration is 0.002 s.