The source and sink temperatures of a Carnot engine are
400 K and 300 K, respectively. What is its efficiency?
(a) 100% (b) 75%
(c) 33.3% (d) 25%
Answers
Answered by
0
Answer:
It is given that T = 400 K and t = 300 K
These are the temperatures of source and sink respectively.
The efficiency of the cycle is,
η=1−
T
t
η=1−0.75=0.25
Thus the efficiency is 25 %
Similar questions