Question

The space between the plates of the parallel plate capacitor is filled with

two slabs of linear dielectric material. Each slab has the thickness so

that the total distance between the plates is 2. The first slab has the value

of dielectric constant as 2 and the second slab has dielectric constant as

1.5. The free charge density on the top surface is and on the bottom

surface is -. Find out the value of polarization on each slab. Also find

out the potential difference between the plates along with the location and

amount of all bound charges.​

Answer 1

Answer:

The presence of the dielectric material therefore reduces the electric field by a factor K. The space between the plates of a parallel-plate capacitor (see Figure 4.10) is filled with two slabs of linear dielectric material. Each slab has thickness s, so that the total distance between the plates is 2s.

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