Question

The space inside a toroid is filled with tungsten whose permeability is 6.8 x 10-5. The percentage increase in the magnetic field will be :-
(1)5.314%
(2)53.14%
(3) 5314%
(4) none of the above​

Answer 1

Answer:

(4) none of the above is the answer

Answer 2

The percentage increase in the magnetic field is $6.8\times10^{-3}\ \%$

(4) is correct option.

Explanation:

Given that,

Permeability $\chi= 6.8\times10^{-5}$

We know that,

The magnetic field  in the absence of tungsten

$B_{0}=\mu_{0}H$

The magnetic field in the presence of tungsten

$B=\mu H$

$B=\mu_{0}(1-\chi_{m})H$

We need to calculate the increase in magnetic field induction

Using formula of magnetic field

$B_{0}-B=\mu_{0}H-\mu_{0}(1-\chi_{m})H$

$B_{0}-B=\mu_{0}\chi_{m}H$

We need to calculate the percentage increase in the magnetic field

Using formula of percentage increase

$Percentage\ increase=\dfrac{B_{0}-B}{B_{0}}\times100$

$Percentage\ increases=\dfrac{\mu_{0}\chi_{m}H}{\mu_{0} H}\times100$

Put the value into the formula

$Percentage\ increase =6.8\times10^{-5}\times100$

$Percentage\ increase =6.8\times10^{-3}\ \%$

Hence, The percentage increase in the magnetic field is $6.8\times10^{-3}\ \%$

Learn more :

Topic : magnetic field

https://brainly.in/question/8378339