Question

The space shuttle travels at a speed of about 7×103 m/s. The blink of an astronaut’s
eye lasts about 110 ms. How much distance does the shuttle cover in the blink of an
eye?

Answer 1

Answer:

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Explanation:

Statement of the given problem,

The Space Shuttle travels at a speed of about 7.6 x 10^3 m/s. the blink of an astronaut’s eye lasts about 110 ms. Shuttle cover in the blink of an eye?

According to above data,

the required number of football fields

= (110/1000)*(7.6*10^3)/91.4 = 9.15 ≈ 9 [Ans]

Answer 2

Given: The space shuttle travels at a speed of about 7×10³ ms⁻¹. The blink of an astronaut’s eye lasts about 110 ms.

To find: Distance covered by the shuttle in the blink of an eye.

Solution:

• Speed of an object is the distance covered by it with respect to time.
• It can be represented by the formula,

        $s = \frac{d}{t}$

• Here, d is the distance covered by the space shuttle, t is the time taken for the blink of an eye and s is the speed of the space shuttle.

• The blink of an astronaut’s eye lasts about 110 milliseconds that can be converted into seconds as,

        $\frac{110}{100} = 1.1 s$

• Now, the distance covered can be calculated as,

        $7 * 10^{3} ms^{-1} = \frac{distance}{1.1}$

                            $= 7.7 * 10^{3} m$

Therefore, the distance covered by the shuttle in the blink of an eye is 7.7×10³ m.