The spacecraft of mass M moves with velocity V in free space at first, then it explodes
breaking into two pieces. If after explosion a piece of mass m comes to rest, the other piece of spacecraft will have a velocity
a. Greater than initial velocity V
b. Lesser than initial velocity V
c. Equal to initial velocity V
d. Equal to 0
Answers
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4
Answer:
Equal to 0 ok
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Answered by
2
Initial momentum of the system P
i
=MV
Let the mass of one part be m
Its velocity V=0
So, mass of other part m
′
=M−m
Let its velocity be V
′
.
Final momentum of the system P
f
=mV+m
′
V
′
Or P
f
=0+(M−m)V
′
=(M−m)V
′
Applying the conservation of linear momentum P
f
=P
i
∴ (M−m)V
′
=MV
⟹ V
′
=
M−m
MV
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