The spacing between the orbits of atoms in terms of distance
is maximum in the case of
(a) 1st and 2nd (b) 2nd and 3rd
(C) 3rd and 4th (d) 4th and 5th
Answers
Radius of Bohr orbit(R
n
) = R
0
z
n
2
where R
0
=0.529A
For hydrogen atom,
R
3
=R
0
1
9
=9R
0
=4.761A
R
2
=R
0
1
4
=4R
0
=2.116A
R
3
−R
2
=5R
0
=2.645A=2.645×10
−8
cm
The distance between third and second Bohr orbit of hydrogen atom is 2.645×10
−8
cm.
Answer:
The spacing between the orbits of atoms in terms of distance is maximum in the case of
(d) 4th and 5th
Explanation:
The Bohr radius is approximately equal to the most probable distance in the ground state between the nucleus and the electron in a hydrogen atom.
The radius of nth Bohr's orbit = n²k, where k is the constant.
For n=1, Radius = 1 k
For n=2, Radius = 4 k
For n=3, Radius= 9 k
For n=4, Radius = 16 k
For n=5, Radius = 25 k
Thus, the maximum spacing between the orbits in the terms of distance will be in 4th and 5th orbit which can be calculated as:
The difference between 4th and 5th orbit = 25 k-16 k = 9 k
Hence, the correct option is D i.e. 4th and 5th.
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