Math, asked by guri78, 1 year ago

the spec of dust in an electron microscope is 1.2 multiplied 10 raise to power 2 mm wide the images 5 multiply 10 raise to power 2 times larger than the actual size how many millimetre wide is the actual speck of the dust the answer is 0.24 mm please solve IT Solution how it is it would be solved

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Answered by himanshusingh52
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High SchoolMathematics5 points

A speck of dust in an electron microscope is 1.2x10^2 millimeters wide. The image is 5x10^2 times larger than the actual size. How many millimeters wide is the actual speck of dust?

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nobillionaireNobleyAmbitious

Let the actual size be x, then
(5 x 10^2)x = 1.2 x 10^2
x = (1.2 x 10^2 / 5 x 10^2) = 0.24 millimeters

Therefore, the actual size is 0.24 millimiters.

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Lampa20Ambitious

Let d be the width of dust seen in electron microscope.
d = 1.2* 10^2 mm

let x be the scaling parameter.
x = 5*10^2mm

dusts actual width D is calculated by scaling d by a factor of x

D = d/x
D =  0.24mm

Note that you are scaling dimensions by a factor of x and not surface of the dust.

Answered by qwwestham
11

GIVEN :

The spec of dust in amicroscope is 1.2× 10^ 2 mm wide

the images5× 10^2 times larger than the actual size

TO FIND :

How many millimetre wide is the actual speck of the dust ?

SOLUTION :

◆Let the actual size of dust be x, then

◆Image is , 5×10^2 times larger than the actual size, which is equal to 1.2 ×10^2 times the magnification of microscope.

◆Let equation be,

(5 x 10^2)x = 1.2 x 10^2

◆x = (1.2 x 10^2 )/(5 x 10^2)

= 0.24 mm.

◆Thus,actual size is 0.24 mm.

Hence proved.

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