THE SPECIAL NUMBER
There is a number whose double is greater than its half
by 45.
Can you find this number?
Answers
Answered by
6
Let the number be 'x'
Given 2x is 45 greater than x/2
⇒ 2x-x/2 = 45
⇒ 3x/2 = 45
⇒ 3x = 45×2
⇒ 3x = 90
⇒ x = 90/3 = 30 .
Therefore the number is 30 .
Given 2x is 45 greater than x/2
⇒ 2x-x/2 = 45
⇒ 3x/2 = 45
⇒ 3x = 45×2
⇒ 3x = 90
⇒ x = 90/3 = 30 .
Therefore the number is 30 .
Answered by
5
let the no.be x,then,
2x = x/2 + 45
2x - x/2 = 45
(4x-x)/2 = 45
3x/2 = 45
3x = 90
hence,x = 90/3 = 30
2x = x/2 + 45
2x - x/2 = 45
(4x-x)/2 = 45
3x/2 = 45
3x = 90
hence,x = 90/3 = 30
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