Question

The species with a radius less than that of Ne is
(a) Mg²⁺
(b) F⁻
(c) O²⁻
(d) K⁺

Answer 1

Answer:

Mg +2

Explanation:

We know that in periodic table, the atomic and ionic size increase down the table due to addition of an extra orbit and decreases across the table.

And larger is the no. of electrons in outermost shell, smaller will be the ionic radii, By the latter explained method, we can say that Mg+2 will have the smallest radius among all the given species.

Answer 2

Answer: Mg 2+

Explanation:

Since all the above species have same no of electrons so the given elements are isoelectronic.

Since all the above species have same no of electrons so the given elements are isoelectronic.The ionic radii of isoelctronic species will increase with decresing magnitude of nuclear charge.

Since all the above species have same no of electrons so the given elements are isoelectronic.The ionic radii of isoelctronic species will increase with decresing magnitude of nuclear charge.02-<F-<Ne<k+<mg2+

Since all the above species have same no of electrons so the given elements are isoelectronic.The ionic radii of isoelctronic species will increase with decresing magnitude of nuclear charge.02-<F-<Ne<k+<mg2+so ions of magnesium will have less ionic radii than Ne