Question

The specific conductance of a 0.1 N KCl solution at 23°C is
0.012 ohm⁻¹cm⁻¹. The resistance of cell containing the
solution at the same temperature was found to be 55 ohm.
The cell constant will be
(a) 0.142 cm⁻¹ (b) 0.66 cm⁻¹
(c) 0.918 cm⁻¹ (d) 1.12 cm⁻¹

Answer 1

answer : option (b) 0.66 cm-¹

The specific conductance of 0.1N KCl solution at 23°C is 0.012 ohm-¹cm-¹

i.e., k = 0.012 ohm-¹cm-¹

the resistance of containing solution, R = 55 Ω

so, conductance , C = 1/R = 1/55 ohm-¹

now, cell constant = specific conductance/conductance

⇒cell constant = k/C = 0.012/(1/55)

= 0.012 × 55 cm-¹

= 0.66 cm-¹

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Answer 2

Answer:

_______0.66cm^-1________