Question

The specific conductance of saturated solution of CaF2 is 3.86*10^-5 and that of water is 0.15*10^-5.the specific conductance of CaF2

Answer 1

Specific conductance of saturated solution = Specific conductance of water + Specific conductance of Ca$F_{2}$

Given that,

Specific conductance of saturated solution = 3.86 × $10^{-5}$

Specific conductance of water = 0.15 × $10^{-5}$

Therefore,

Specific conductance of Ca$F_{2}$ = [ 3.86 × $10^{-5}$ ]- [ 0.15 × $10^{-5}$ ] = 3.71 × $10^{-5}$

Finally,

Specific conductance of Ca$F_{2}$ = 3.71 × $10^{-5}$

Answer 2

Hope you get the answers