Chemistry, asked by karimunnisabegumshai, 10 months ago

the specific gravity of 84% w/w H2SO4 is 1.752.the normality of solution is

Answers

Answered by chemisst
9

The normality of solution is 30 N.

Explanation:

Specific gravity = 1.752 g/mL

We will convert it into g/L

Specific gravity = 1752 g/L

% w = 84%

Thus,

0.84×1752  = 1471.68 g/L of H₂SO₄

The equivalent weight of H₂SO₄ is 49.

Molecular weight of H₂SO₄ is 98. Thus,

1 N H₂SO₄ is 49 g/L

1471.68 g/L / 49 g/L =  30 N

Answered by jaswasri2006
0

 \huge \tt 30  \: N

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