Question

The Specific gravity of a liquid column is 0.75 .What height of that liquid is needed to provide a pressure difference of 200 kPa? 
​

Answer 1

Explanation:

Using the Formula,

Pressure(P) = hρg

= 0.75×1300×9.8

= 9555 Pa.

Hence, the Pressure is 9555 Pa.

For Finding the Pressure in C.G.S. System,

Height of the Mercury Column(h) = 75 cm.

Acceleration due to gravity(g) = 9.8m/s

2

=9.8×100cm/s

2

=980cm/s

2

.

Density of the Water =1000kg/m

3

.

= 1000×10

6

g/10

6

cm

3

.

= 10

6

/10

6

g/cm

3

.

= 1g/cm

3

∴ Density of the Mercury(ρ) = Specific Gravity of the Mercury × Density of the Water.

=1.3×1

=1.3g/cm

3

.

Now Using the Formula,

Pressure(P)= hρg

= 75×1.3×980

= 9550 Ba.