Question

The specific gravity of an oil whose specific weight is 7.85 kn/m3 is

Answer 1

Specific weight of oil/specific weight of water.

SPECIFIC WEIGHT OF WATER = 9.81 KN/m3.

7.85 /9.81 = 0.8 unit less.

Answer 2

Answer:

The oil's specific gravity measured is $0.80$.

Explanation:

Given,

The specific weight of the oil, $W_{oil}$ = $7.85kN/m^{3}$

The specific gravity of the oil =?

Now, we know that the specific weight of the water, $W_{water}$ is $9.8kN/m^{3}$.

As we know,

• The specific gravity of the oil = $\frac{W_{oil} }{W_{water} }$

After putting the given values in the equation, we get:

• The specific gravity of the oil = $\frac{7.85}{9.8}$ = $0.80$

Hence, the specific gravity of the oil = $0.80$.