The specific gravity of the material of a body is
determined by weighing the body first in air and
then in water. If the weight in air is 10.0+ 0.1 gf
and weight in water is 5.0+0.1 gf, then what
is the maximum possible percentage error in the
specific gravity.
Answers
Answer:
Given,
weight in air = (10 + 0.1) N
weight in water = (5 ± 0.1) N
∴ Loss of weight in water = weight in air - weight in water
= (10 ± 0.1) N - (5 ± 0.1) N
= (10 - 5) ± (0.1 + 0.1) [ in case of error , you should always take addition ]
= (5 ± 0.2) N
Now, relative density = weight in air /loss of weight in water
= (10 ± 0.1)N/(5 ± 0.2)N
= (10/5) ± [0.1/10 + 0.2/5] × 100
[ Actually, % error = [∆w/W + ∆w'/W']×100 , here w is weight in air and w' is loss of weight in water ]
= 2 ± [1 + 4]%
= 2 ± 5%
hence, maximum % error = 5%
hope you like it.........
pls mark me the brainliest..........
The maximum possible percentage error in the specific gravity is 5%.
Given:
- weight in air = (10 + 0.1) N
- weight in water = (5 ± 0.1) N
To Find:
The maximum possible percentage error in the specific gravity
Solution:
- weight in air = (10 + 0.1) N
- weight in water = (5 ± 0.1) N
Loss of weight in water = [weight in air - weight in water]
= (10 ± 0.1) N - (5 ± 0.1) N
= (10 - 5) ± (0.1 + 0.1) [ in case of error , you should always take addition ]
= (5 ± 0.2) N
Now, relative density = [weight in air /loss of weight in water]
= (10 ± 0.1)N/(5 ± 0.2)N
= (10/5) ± [0.1/10 + 0.2/5] × 100
[ Actually, % error = [∆w/W + ∆w'/W']×100 , here w is weight in air and w' is loss of weight in water ]
= 2 ± [1 + 4]%
= 2 ± 5%
Hence, the maximum possible percentage error in the specific gravity is 5%.
#SPJ3