Question

the specific heat of a gas at constant volume is 0.075cal/g, predict the atomicity of the gas. molar mass of gas is 40g/mole

Answer 1

$C_v=0.075\ cal/g\\molar\ mass=40\ g/mole\\C_v=0.075 \times 40=3\ cal/mole\\ \\let\ C_v=x \times R\\ \Rightarrow 3=x \times 1.988\\ \Rightarrow x= \frac{3}{1.988} \approx1.5\\ \\Thus\ it\ is\ a\ monoatomic\ gas.$

Answer 2

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$C_v=0.075\ cal/g\\molar\ mass=40\ g/mole\\C_v=0.075 \times 40=3\ cal/mole\\ \\let\ C_v=x \times R\\ \Rightarrow 3=x \times 1.988\\ \Rightarrow x= \frac{3}{1.988} \approx1.5\\ \\Thus\ it\ is\ a\ monoatomic\ gas.$

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