The specific heat of a gas is found to be 0.075 calories at constant volume and its formula weight is 40. The atomicity of the gas would be
(1) One
(2) Two
(3) Three
(4) Four
choose the correct option
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Answers
Answered by
2
Answer:
Total Heat=40×0.075=3cal=Cv
Cp−Cv=R
Cp=Cv+R
=3+2
=5cal
Cv
Cp
=
3
5
=monoatomic
Answered by
1
Answer:
1)one
Explanation:
Total Heat=40×0.075=3cal=Cv
Cp−Cv=R
Cp=Cv+R
=3+2
=5cal
Cv/cp=5/3
=monoatomic.
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