Question

The specific heat of a gas is found to be 0.075 calories at constant volume and its formula weight is 40. The atomicity of the gas would be One Two Three Four

Answer 1

Specificheat of gas at constant volume=0.075calg^-1C° i.e,0.075cal is absorbed by 1g of it for 1° rise in temperature at constant volume.So,total heat absorbed by 1g mole of the gas is 40(0.075)=3cal.Since,Cp-Cv=R or Cp=5 Cp/Cv=5/3 & hence the gas is monatomic.

Answer 2

Specificheat of gas at constant volume =0.075 cal g-1Co

i.e., 0.075cal is absorbed by 1g of it for 10rise in temperature at constant volume.

So, total heat absorbed by 1g mole of the gas is 40(0.075) = 3 cal.

Since , Cp - Cv = R or Cp = 5

Cp/Cv= 5/3 and

hence the gas is monatomic.

ANS : 1