The specific heat of a material is given in a strange unit to be c = 3.60 kJ/kg.°F. The specific heat of this material in the SI units of kJ/kg. °C is 2.00 kJ/kg. c 3.20 kJ/kg. °C 3.60 kJ/kg.'c 6.48 kJ/kg . °C
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Given info : The specific heat of a material is given in a strange unit to be c = 3.6 kJ/kg.°F
To find : the specific heat of this material in the SI unit of KJ/kg.°C is..
solution : if you consider the formula of heat change of a material, you get, H = msΔT , means the specific heat depends on the change in temperature.
we also know, change in temperature in °C = 5/9 × change in temperature in °F
⇒ if we consider change in temperature in °F is 1 then change in temperature in °C will be 5/9.
∴ 1°C = 5/9°F
∴ 1°F = 9/5 °C
so the specific heat of the material in the si units = 3.6 kJ/kg(9/5°C)
= 2 kJ/kg.°C
therefore the specific heat of the material in the SI units is 2.00 kJ/kg.°C
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