Chemistry, asked by SHUBH123123, 1 year ago

THE SPECIFIC HEAT OF A METAL IS 0.836j/g.THE APPROX at.wt is?

Answers

Answered by Anonymous
9
acc to dulong and petit's law:-
specific heat multiplied by at. wt = 6.4
so,
0.836*at wt= 6.4
at.wt=6.4 / 0.836, which is equal to 7.7j/g
the element must be lithium


SHUBH123123: thanks.......for ur help
Anonymous: my pleasure!!!!
Answered by RomeliaThurston
6

Answer: The atomic weight of the metal is 7.65 g

Explanation:

Dulong and Petit's law states that the product of the specific heat capacity of a solid element and its mass per mole is always constant which is 6.4

Mathematically,

\text{Atomic weight}\times \text{Specific heat}=6.4

We are given:

Specific heat of the metal = 0.836 J/g

Putting values in above equation, we get:

\text{Atomic weight}=\frac{6.4}{0.836}=7.65

Hence, the atomic weight of the metal is 7.65 g

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